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发表于 12-11-2009 11:44 PM
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到我有问题了
头要爆了
我分不清reduce和oxidised
在light reaction,
splitting of water can produce hydrogen ion by photolysis
这个hydrogen ion then combine with the electron of PS 1,
对不对?
然后produce NADPH^+ + H^+ 吗?
所以是reduce NADP to NADPH????????????? |
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发表于 13-11-2009 12:12 AM
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During photolysis,water split into Oxygen and Proton with electron.
Electron is used to oxidise PS II system,since PS II system had loss electron due to photoactivation. Proton are used either in production of ATP or Reduction of NADH.
i)Reduction of NADP is occur at last stage of non-cyclic photophosporylation in which NADP is reduced into NADPH + H WHICH is catalysed by NADP reductase.
ii)Proton is flow into thalakoid space along the concentration through cytochrome b6f complex,which is essential process for ATP production in chemiosmosis process.It can occur either in cyclic or non-cyclic phosphorylation process. |
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发表于 13-11-2009 01:00 AM
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发表于 13-11-2009 02:49 PM
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formation of ATP by chemiosmosis 不是respiration那课吗??
then Photolysis produces electrons 和 protons (H+) 和 oxygen。
这个H+不 combine NADP+ ,then NADPH怎样formed??
那calvin cycle 不能发生了
谢谢你们=) |
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发表于 13-11-2009 03:19 PM
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发表于 13-11-2009 03:23 PM
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但是calvin cycle不是要用NADPH of light reaction的吗?
formation of ATP 不是当electron pass thro a series of electron carrier 才produce的瓦 |
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发表于 13-11-2009 04:17 PM
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原帖由 purple_pig_33 于 13-11-2009 03:23 PM 发表 
但是calvin cycle不是要用NADPH of light reaction的吗?
formation of ATP 不是当electron pass thro a series of electron carrier 才produce的瓦
对,calvin cycle是要用NADPH from light reaction.
所以我说了,photolysis的H+并没有combine with PSI,
但不代表NADPH不可以被formed。
NADP+是因为接受了electrons from PSI和H+ from stroma,才变成NADPH。
所以一样有form NADPH。有NADPH,就有Calvin cycle 咯。
对,formation of ATP是当electron pass through a series of electron carrier 才produce的。没有错。
但是,我们也必须要会解释为什么会这样。
原因是因为当electron pass through a series of electron carrier时,energy is released,
那些energy被b6f complex用来将stroma的H+ pumps去thylakoid space 里面,
以便制造proton gradient。有了proton gradient,就可以有chemiosmosis。
那些thylakois space的H+如果要出回来stroma,就一定要经过ATP synthase located in the thylakoid membrane。当H+ pass through ATP synthase,ATP就会被制造。
这就是chemiosmosis的photophosphorylation。 |
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发表于 13-11-2009 04:40 PM
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发表于 13-11-2009 06:38 PM
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原帖由 purple_pig_33 于 2009/11/12 03:39 PM 发表 
irreversible的应该没有competitive inhibitor
对吧?
所以说
inhibitor can be reversible and irreversible.
reversible 可以再分成 competitive and non-competitive
competitive compete with the subtra ...
改正一下,example of competitive inhibitor is malonate which competes with succinate for the active site in succinate dehydrogenase .
Example of irreversible incompetitive inhibitor is cyanide ions which inhibits the cytochrome oxidase in Electron Transport System. [muscle contraction 的是curare which competes with acetylcholine for active site of the protein receptor in post synaptic membrane causes paralysis]
Reversible incompetitive inhibitors are usually those that take part in end-product inhibition.
For example, threonine ---------- > isoleucine ; catalysed by enzyme threonine deaminase; when the concentration of isoleucine is high, it will bind to the allosteric site of threonine deaminase, making it unsuitable for theonine. So the reaction is inhibited.
*这个其实是negative feedback mechanism.Increase in concentration of isoleucine will inhibit the activity of enzyme threonine deaminase.

我觉得当一个人觉得bio很难读的话,他肯定有以下问题
i)没有好的参考书
ii)没有优质的老师
iii)他不喜欢biology
这个问题很容易解决
i)http://intranet.col-westanglia.ac.uk/storage/resources_net/curriculum-press/ ; 去下载那biology fact sheets
ii) 去买或下载好的参考书(campbell and reece, biochemistry for dummies, www.biologyguide.net , www.johnyrk.com
iii)用对的方法读书。
iv)用心去读
[ 本帖最后由 darksider 于 14-11-2009 11:29 AM 编辑 ] |
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发表于 13-11-2009 06:52 PM
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发表于 13-11-2009 06:52 PM
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原帖由 darksider 于 11-11-2009 02:30 PM 发表 
Anaerobic respiration
If oxygen is unavailable the Kreb’s cycle and electron transfer chain
cannot operate. This is because without oxygen there would be no
way of disposing of the hydrogen at, fo ...
我也来个补充...
SUPPOSE 有4 ATP FORMED.... 不过GLYCOLYSIS 前面的STEPS 有用到2 ATP 所以NETT 是 2 ATP~
CARI 有好多BIO 高人哦~~ |
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发表于 13-11-2009 07:05 PM
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原帖由 carly_yen 于 2009/11/11 07:32 PM 发表 
我觉得好象是INELASTIC....
因为是TOUGH MEMBRANE, SUPPOSE TO BE INELASTIC....
IF IT'S FUNCTION IS TO PREVENT THE HEART FROM THE OVERFILLED WITH BLOOD, 那么如果是ELASTIC的话,不就根本就不能CARRY OUT THI ...
那pericardium sarc是一个inelastic的membrane.它的主要功能是把fix住心脏的位置和prevent the heart from overstretching (which is resulted from being overfilled with blood). |
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发表于 13-11-2009 07:08 PM
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回复 372# darksider 的帖子
老实说... 这时哪一课的啊~~?? 哈哈哈~~
我好象没有读过......
我用COMMON SENSE回答罢了........
谢谢解答! |
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发表于 13-11-2009 07:10 PM
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原帖由 carly_yen 于 2009/11/13 07:08 PM 发表 
老实说... 这时哪一课的啊~~?? 哈哈哈~~
我好象没有读过......
我用COMMON SENSE回答罢了........
谢谢解答!
Transport那课...新的oxford fajar课本有提到。 |
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发表于 13-11-2009 07:12 PM
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请问BIO PAST YEAR 出过的题目还会再出吗???? |
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发表于 13-11-2009 07:25 PM
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原帖由 darksider 于 13-11-2009 07:10 PM 发表 
Transport那课...新的oxford fajar课本有提到。
难怪.... 我用PELANGI 的~~~~~ 哈哈哈!
大家一起加油! |
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发表于 13-11-2009 07:58 PM
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发表于 13-11-2009 10:48 PM
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原帖由 darksider 于 13-11-2009 06:38 PM 发表 
改正一下,example of competitive inhibitor is malonate which competes with succinate for the active site in succinate dehydrogenase .
Example of irreversible incompetitive inhibitor is cyanide ...
謝謝你的改正 |
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发表于 13-11-2009 11:54 PM
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原帖由 darksider 于 13-11-2009 06:52 PM 发表 
我学到的是photolysis occurs in the lumen of the thylakoid.photolysis所产生的H+ ions are used in the formation of NADPH...
the only molecule that can oxidise water is P680, a reacion centre Phot ...
哇!你讲解的很详细。
对啊,NADP+是因为接受了stroma的H+,才被reduced成为NADPH。
很多图片都是这样画的。 |
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发表于 14-11-2009 12:01 AM
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原帖由 darksider 于 13-11-2009 07:58 PM 发表 
我想应该不会出同样的问题,但同样的topic就会。
上次听一位chemistry marker说,有些比较懒惰的examiners会用bank questions里面的考题来出(比如那些questions出现在2002 trial,他们4-5年后会出在STPM.. ...
但是看了那么多年的past year objective都好像没有问过chordae tendinae and papillary muscle。
这个会不会detail了一点? |
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