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发表于 13-12-2010 11:05 PM
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回复 320# whyyie
regression 几时有group data的?
哪里来的mid point  |
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发表于 13-12-2010 11:18 PM
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回复 321# peaceboy
写错了...用coding时是拿中间的data还是拿first data 来减掉? |
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发表于 13-12-2010 11:25 PM
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回复 322# whyyie
coding的用意就是要把复杂难算的data简单化
比如说吧x是五位数的data,我们就把它coding成一位数,通常是减掉一些数目
如果说x是有decimal的data,我们就乘10来解决掉decimal
至于有没有规定用什么来coding,这我没有去研究过 
反正就是把data变简单就是了 |
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发表于 14-12-2010 10:46 AM
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发表于 14-12-2010 09:36 PM
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回复 324# whyyie
i) 抄2的问题 - - ,the probability that u lie between the interval is 0.95
ii) yes. = =reason 不懂怎样写
iii) 0.95 * 120 呱
{:2_74:} 怪怪的问题 |
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发表于 15-12-2010 01:10 AM
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The results of a survey showed that 3600 out of 10000 families regularly purchased a specific weekly magazine .
a)Find the approximate 95% confidence limits for the proportion of families buying the magazine.
b)Estimate the additional number of families to be contacted if the probability that the estimated proportion is in error by more than 0.01 is to be at most 1%
Answer: a)0.36+-9.408x10^-3
b)n=5277
Can anyone show me that working? |
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发表于 15-12-2010 05:57 PM
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回复 326# 數學神童
p = 0.36
sample var = 0.36*0.64/10000
confident interval = 0.36 +- 1.96*( 0.36*0.64/10000)^(1/2)
=0.36+-9.408x10^-3
2.576 (0.36*0.64/n)^(1/2) > 0.01
n<(2.576/0.01)^2 * 0.36*0.64
n<15288.82
n= 15288
addition = 5288
= =乱来的{:2_82:} |
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发表于 19-12-2010 07:04 PM
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Network planning 画出来的network需不需要是shortest path?
是不是要尽量避免使用dummy activity? |
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发表于 19-12-2010 07:59 PM
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回复 328# whyyie
你不是考完了还问 = =
需要dummy 就要用dummy。
最后答案只会有一种
一般都是很简单的拉.... |
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发表于 19-12-2010 11:54 PM
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回复 329# peaceboy
我是拿Maths T 的, 现在是读爽.
不过我画的都和书不同. |
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发表于 20-12-2010 07:01 PM
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回复 330# whyyie
理论上是不会不一样的
要注意的是同一个event去下一个event 不可能有两条线
如
_______1__________〉
0________2_________〉0
这种情况是不可以发生的
另外也不可出现cycle 的现象
用dummy 解决 |
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发表于 20-12-2010 08:17 PM
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本帖最后由 whyyie 于 20-12-2010 08:27 PM 编辑
不懂哦... 答案有一题是没有event,不过线是直的, 没有------> 算是dummy啊?
还有federal和longman的earliest start event 和latest start event 都画不同的,
而且算event时的presentation也不同
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发表于 20-12-2010 08:47 PM
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回复 332# whyyie
我们是根据左边那种
算的方法理论上是一样的。 |
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发表于 20-12-2010 09:00 PM
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回复 333# peaceboy
你们是用哪一种方法?
Event 4:
d= maximum{1+2, 3+3}
= maximum {3, 6}
= 6
__________________________________
Event 3: There are two possibilities
Earliest time A(3)
= A(2) + duration of activity D
= 2 + 6
= 8
Earlies time A(3)
= A(1) + duration of activity B
= 0 + 4
= 4
Thus, we pick 8. |
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发表于 24-12-2010 06:09 PM
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回复 334# whyyie
下面那个呱
没有图解释很麻烦 {:2_80:} |
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发表于 12-1-2011 06:30 PM
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pn fatimah send 10 applicationforms for new shares issue.If the prbability of sucess for each applicatin is 10%,find the probability that she is successful in a)4applications or less
是P(x<=4)还是P(0<=x<=4) |
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发表于 12-1-2011 07:22 PM
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回复 336# hongji
两个不是都一样 |
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发表于 25-1-2011 10:33 PM
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x~N(82,2.25),Y~N(42,0.09) and Z~N(85,0.49)
find a)p[x>2(z-y)]
b)p(3x>6y)
怎样把x y z分开? |
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发表于 26-1-2011 07:06 PM
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发表于 26-1-2011 08:37 PM
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回复 hongji
x~N(82,2.25),Y~N(42,0.09) and Z~N(85,0.49)
find a)p[x>2(z-y)]
b)p(3x>6y)
...
peaceboy 发表于 26-1-2011 07:06 PM 
stpm可以看log book的吗?
这题是数学paper2的啊。。 |
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