佳礼资讯网

 找回密码
 注册

ADVERTISEMENT

楼主: nejiru

槟城恒毅中学交流区续篇

 关闭 [复制链接]
发表于 23-2-2008 11:09 AM | 显示全部楼层
原帖由 khookw64 于 22-2-2008 21:11 发表


因为读bio 人说话比较深麻。。我凡夫怎么懂

这里大家都是凡夫俗子,没有贵贱之分,不懂就讲不懂... 知之为知之,不知为不知,是智也...
回复

使用道具 举报


ADVERTISEMENT

 楼主| 发表于 23-2-2008 06:45 PM | 显示全部楼层
原帖由 LOO5O 于 23-2-2008 11:09 AM 发表

这里大家都是凡夫俗子,没有贵贱之分,不懂就讲不懂... 知之为知之,不知为不知,是智也...
对啊!!!
回复

使用道具 举报

发表于 23-2-2008 07:33 PM | 显示全部楼层
原帖由 LOO5O 于 23-2-2008 11:09 AM 发表

这里大家都是凡夫俗子,没有贵贱之分,不懂就讲不懂... 知之为知之,不知为不知,是智也...



是知也
回复

使用道具 举报

发表于 23-2-2008 09:35 PM | 显示全部楼层
原帖由 khookw64 于 23-2-2008 19:33 发表



是知也

我用的是文言文,以前人都是想不到字时就用另一个同音的字代替它。你们读中国文学的应该知道吧?
回复

使用道具 举报

发表于 23-2-2008 09:49 PM | 显示全部楼层
原帖由 LOO5O 于 23-2-2008 09:35 PM 发表

我用的是文言文,以前人都是想不到字时就用另一个同音的字代替它。你们读中国文学的应该知道吧?


  还敢绞辩。。。。。。。。:@
回复

使用道具 举报

发表于 23-2-2008 09:55 PM | 显示全部楼层
原帖由 khookw64 于 23-2-2008 21:49 发表


  还敢绞辩。。。。。。。。:@

没有狡辩,不相信可以去查你的书!
回复

使用道具 举报

Follow Us
发表于 24-2-2008 07:39 AM | 显示全部楼层
原帖由 rainniy 于 22-2-2008 08:55 PM 发表
人造的,你不会懂的。。。。。。


对,他不懂的...
回复

使用道具 举报

发表于 24-2-2008 07:41 AM | 显示全部楼层
原帖由 khookw64 于 23-2-2008 09:49 PM 发表


  还敢辩。。。。。。。。:@


你也用错字...
辩...
回复

使用道具 举报


ADVERTISEMENT

发表于 24-2-2008 07:43 AM | 显示全部楼层
原帖由 khookw64 于 22-2-2008 09:11 PM 发表
因为读bio 人说话比较深麻。。我凡夫怎么懂


你有什么懂的?
学会活动都可以见周公的查帐...
回复

使用道具 举报

发表于 24-2-2008 07:44 AM | 显示全部楼层
无聊完了...
继续K书...
回复

使用道具 举报

发表于 24-2-2008 09:32 AM | 显示全部楼层
原帖由 Qim4Y_Gem$Gal 于 24-2-2008 07:44 发表
无聊完了...
继续K书...

勤力的猫....
回复

使用道具 举报

 楼主| 发表于 26-2-2008 06:48 PM | 显示全部楼层
我来救帖了!!!!
回复

使用道具 举报

 楼主| 发表于 26-2-2008 10:02 PM | 显示全部楼层
什么是buffer solution??????????
回复

使用道具 举报

发表于 27-2-2008 05:07 PM | 显示全部楼层

回复 293# nejiru 的帖子

去STPM专区求助啦!
回复

使用道具 举报

发表于 27-2-2008 05:09 PM | 显示全部楼层

回复 293# nejiru 的帖子

去STPM专区求助啦!
回复

使用道具 举报

发表于 27-2-2008 08:34 PM | 显示全部楼层
大家好~
我又回来走走,顺便拿分
回复

使用道具 举报


ADVERTISEMENT

发表于 27-2-2008 09:16 PM | 显示全部楼层
原帖由 nejiru 于 26-2-2008 10:02 PM 发表
什么是buffer solution??????????


应该是chemistry的吧。

HA(aq) + H2O(l) → H3O+(aq) + A−(aq)      ,恩给你一个formula了。

  给你notes :


Buffer solutions are solutions that resist change in Hydronium ion and the hydroxide ion concentration (and consequently pH) upon addition of small amounts of acid or base, or upon dilution. Buffer solutions consist of a weak acid and its conjugate base (more common) or a weak base and its conjugate acid (less common). The resistive action is the result of the equilibrium between the weak acid (HA) and its conjugate base (A&#8722:
HA(aq) + H2O(l) → H3O+(aq) + A−(aq) Any alkali added to the solution is consumed by the Hydronium ions. These ions are mostly regenerated as the equilibrium moves to the right and some of the acid dissociates into Hydronium ions and the conjugate base. If a strong acid is added, the conjugate base is protonated, and the pH is almost entirely restored. This is an example of Le Chatelier's principle and the common ion effect. This contrasts with solutions of strong acids or strong bases, where any additional strong acid or base can greatly change the pH. This may be easier to see by comparing two graphs when an strong acid is titrated with a strong base the curve will have a large gradient throughout showing that a small addition of base/acid will have a large effect compared to a weak acid/strong base titration curve which will have a smaller gradient near the pKa.

When writing about buffer systems they can be represented as salt of conjugate base/acid, or base/salt of conjugate acid. It should be noted that here buffer solutions are presented in terms of the Brønsted-Lowry notion of acids and bases, as opposed to the Lewis acid-base theory (see acid-base reaction theories). Omitted here are buffer solutions prepared with solvents other than water.
回复

使用道具 举报

发表于 27-2-2008 09:18 PM | 显示全部楼层
Calculating pH
The equilibrium above has the following acid dissociation constant:


Simple manipulation with logarithms gives the Henderson-Hasselbalch equation, which describe pH in terms of pKa:


In this equation

[A−] is the concentration of the conjugate base. This may be considered as coming completely from the salt, since the acid supplies relatively few anions compared to the salt lyn.
[HA] is the concentration of the acid. This may be considered as coming completely from the acid, since the salt supplies relatively few complete acid molecules (A − may extract H + from water to become HA) compared to the added acid.
Maximum buffering capacity is found when pH = pKa, and buffer range is considered to be at a pH = pKa ± 1.
回复

使用道具 举报

 楼主| 发表于 28-2-2008 08:37 PM | 显示全部楼层
没人的!!!闷咯!!!祝大家考试愉快啦!!!
回复

使用道具 举报

发表于 29-2-2008 04:25 PM | 显示全部楼层
原帖由 khookw64 于 27-2-2008 21:16 发表


应该是chemistry的吧。

HA(aq) + H2O(l) → H3O+(aq) + A−(aq)      ,恩给你一个formula了。

  给你notes :


Buffer solutions are solutions that resist change in Hydronium ion and the h ...

好!!!
回复

使用道具 举报

您需要登录后才可以回帖 登录 | 注册

本版积分规则

 

所属分类: 欢乐校园


ADVERTISEMENT



ADVERTISEMENT



ADVERTISEMENT

ADVERTISEMENT


版权所有 © 1996-2023 Cari Internet Sdn Bhd (483575-W)|IPSERVERONE 提供云主机|广告刊登|关于我们|私隐权|免控|投诉|联络|脸书|佳礼资讯网

GMT+8, 22-9-2024 06:57 AM , Processed in 0.109805 second(s), 20 queries , Gzip On.

Powered by Discuz! X3.4

Copyright © 2001-2021, Tencent Cloud.

快速回复 返回顶部 返回列表