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发表于 27-7-2011 08:21 PM
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[2x(x^2 + 3) ]/ [ (x^2 -1)^3 ] > 0
这个graph 怎样画?可以教我吗?谢谢 |
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发表于 28-7-2011 10:25 AM
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发表于 28-7-2011 10:27 AM
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回复 2721# hongji
> 0 ? 还是 = 0?是要找x 的range? |
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发表于 29-7-2011 01:11 PM
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given a curve y= x^2 - 4 and a straight line y=x - 2
(a) calculate the area of the region R bounded by the curve and the straight line.
(b)find the volume of the solid formed when R is rotatd through 360 (degree) about the x-xis. |
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发表于 29-7-2011 01:15 PM
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回复 hongji
> 0 ? 还是 = 0?是要找x 的range?
menglee90 发表于 28-7-2011 10:27 AM 
> 0 ...
yes ,find x range and sketch ... |
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发表于 29-7-2011 01:30 PM
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回复 2721# hongji
我只帮你找x的range。
[2x(x^2 + 3) ]/ [ (x^2 -1)^3 ] > 0
Since (x^2 + 3) always > 0 , we only consider 2x/ (x^2 -1)^3
2x/ (x^2 -1)^3 > 0 when 2x and (x^2 -1)^3 are both positive or both negative, x =/= 1, -1
Case 1:
2x>0 and (x^2 -1)^3 > 0
x>0 (x^2 -1) > 0
x<-1 , x>1
Therefore, x>1
Case 2:
2x<0 and (x^2 -1)^3 < 0
x<0 (x^2 -1) < 0
-1<x<1
Therefore, -1<x<0
Combining two cases, x>1 and -1<x<0 |
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发表于 29-7-2011 01:34 PM
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回复 2724# hongji
提示:把graph画出来,找line和curve的intersection point,就知道integrate的limits了。 |
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发表于 30-7-2011 10:41 AM
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回复 2669# peaceboy
Thank you |
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发表于 9-8-2011 08:02 PM
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我想问,
1/2 In 2 + In2
怎样加起来等于3/2 In 2 ... |
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发表于 9-8-2011 08:31 PM
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回复 2729# hongji
和平常做algebra的方法一樣
如: x+2x=3x
3ln2+2ln2=5ln2
x+(1/2)x=(3/2)x
ln2+(1/2)ln2=(3/2)ln2 |
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发表于 9-8-2011 09:49 PM
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我想问,
1/2 In 2 + In2
怎样加起来等于3/2 In 2 ...
hongji 发表于 9-8-2011 08:02 PM 
不然就factorize ln 2出来就可以了。。
(1/2)ln 2+ln 2=[(1/2)+1]ln 2
=(3/2)ln 2 |
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发表于 11-8-2011 02:41 PM
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我想问sketch the graph f(x) =( [4^ekt] + 1 ) / ([4^ekt] - 1 )
when k are constant
怎样画TT |
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发表于 12-8-2011 12:29 AM
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哪一个软件可以帮我们画graph并且可以列出intersection point,max point,min point,inflection pt,roots等等的? |
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发表于 12-8-2011 09:17 AM
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回复 2733# badkids91
可以试试wolframalpha.com
例子:plot x^2+4x+7, 2x+4 |
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发表于 15-8-2011 10:57 AM
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我想问sketch the graph f(x) =( [4^ekt] + 1 ) / ([4^ekt] - 1 )
when k are constant
怎样画 ...
hongji 发表于 11-8-2011 02:41 PM 
4^ekt 还是 4e^kt...?? |
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发表于 16-8-2011 11:43 PM
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4^ekt 还是 4e^kt...??
Log 发表于 15-8-2011 10:57 AM 
是4e^kt.
,我写错了 |
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发表于 27-8-2011 03:14 PM
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5.A variable point P lies on the line x = -4 and O is the origin.A straight line which is parallel to the x-axis and passes through the point P meets the straight line which passes through the origin O and perpendicular to OP at Q. Show that the locus of Q is [y^2] = 4x.
6.A straight line y = m(x - 2)which passes through a fixed point (2,0) meets the lines x = 1 and y = k at A and B respectively.If O is the origin and P is the point (1,0), find the equations of lines OA and PB. If m varies,find the equations of the locus of the point of intersection between lines OA and PB.
这题我找到equation of line OA and PB 但是找不到 equation of the locus of the point of intersection |
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发表于 27-8-2011 06:11 PM
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5.A variable point P lies on the line x = -4 and O is the origin.A straight line which is parallel t ...
hongji 发表于 27-8-2011 03:14 PM 
5) Let P(-4 , a)
Gradient of straight line OP=(a-0)/(-4-0)
= -a/4
Gradient of straight line OQ, (-a/4)M2=-1
M2=4/a
Equation of straight line OQ, y=(4/a)x
When y=a, a=(4/a)x
x=(a^2)/4
Coordinate of Q (a^2/4 , a)
Equation of locus Q:
x=(a^2)/4 , y=a
x=y^2/4
y^2=4x (shown) |
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发表于 27-8-2011 06:28 PM
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5.A variable point P lies on the line x = -4 and O is the origin.A straight line which is parallel t ...
hongji 发表于 27-8-2011 03:14 PM 
Equate equation of straight line OA和PB来找到intesection point。
然后就用parametric来找equation of locus。 |
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发表于 28-8-2011 05:31 PM
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Equate equation of straight line OA和PB来找到intesection point。
然后就用parametric来找equa ...
Allmaths 发表于 27-8-2011 06:28 PM 
如果math paper2 可以A,math paper 1 最少要拿多少能A & B? |
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