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发表于 14-4-2010 06:48 PM
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新问题!谁可以教我Ace Ahead V2 quick check 1.5 第3题?
谢谢!
醉痴雪 发表于 14-4-2010 05:26 PM 
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发表于 14-4-2010 07:05 PM
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回复 242# walrein_lim88
谢谢!
那相同书q.c 1.5 第5题呢? |
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发表于 14-4-2010 09:31 PM
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回复 walrein_lim88
谢谢!
那相同书q.c 1.5 第5题呢?
醉痴雪 发表于 14-4-2010 07:05 PM 
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发表于 15-4-2010 09:31 PM
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发表于 15-4-2010 11:06 PM
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发表于 17-4-2010 12:44 AM
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谁可以帮我解决。。。
oxford fajar Q.C 2.3 Q3 (d) |
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发表于 17-4-2010 03:39 PM
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谁可以帮我解决。。。
oxford fajar Q.C 2.3 Q3 (d)
觉悟-修罗之道 发表于 17-4-2010 12:44 AM 
这里我不会画。。。。。。。
很难解释如果没有SKETCH,除非我在MSN解释给你。。。 |
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发表于 18-4-2010 07:51 PM
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1. a continuous random variable X is such that P(X<x) = mx + c for 1 < x < 5. calculate the values of m and c. Sketch the cumulative distribution function.
2. find the value of k if f(x) = ke^-x is the probability density function for x> 0. find the distribution function and sketch both functions.
3. a continuous random variable X takes values from 0 to 2. The probability that X takes a value greater than x is px^2 + q for 0 <x<2.
(a) determine the value of p and q (b) find the probability density function
4. a continuous random variable takes values from 0 to k. the probability that X takes a value greater than x is mx + 2 for 1<x<k.
(a) determine the value of k and m
(b) find the cumulative distribution function
(c) obtain the probability density function
5. for a continuous random variable, if f(x) = 2e^-2x, where x > 0, show that F(x) = 1- e^-2x. find the median value of x |
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发表于 18-4-2010 10:36 PM
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发表于 20-4-2010 06:10 PM
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发表于 27-4-2010 01:14 AM
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ABCDEF is a regular hexagon with each of its sides measuring p units.By using unit vectors i and j to be along the directions of AB and AE respectively,and given that AB=4i,state the numerical value of p , and show that vector AC=6i+2surd 3 j.Find , in terms of i and j , the vectors AD,AEand AF |
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发表于 29-4-2010 12:21 AM
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发表于 29-4-2010 12:58 AM
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发表于 29-4-2010 12:59 AM
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发表于 29-4-2010 01:00 AM
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发表于 29-4-2010 01:01 AM
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卡帖变就没人帮我做了 |
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发表于 29-4-2010 01:02 AM
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#252 请帮忙  |
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发表于 29-4-2010 08:34 PM
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回复 252# 白羊座aries
还没教到, 不懂(BM 和MC)的做法对不对. AD, AE, AF 自己找找看
numerical value of p = 4
BM = (4 cos 60)i = 2i
MC = (4 sin 60)j = (4 surd 3)j / 2 = (2 surd 3) j
AB
= AM + MC
= (AB + BM) + MC
= (4i + 2i) + (2 surd 3) j
= 6i + (2 surd 3) j |
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发表于 29-4-2010 09:04 PM
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发表于 1-5-2010 10:29 PM
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需要各位的帮忙。。
A family consisting of 3 members A, B and C live in a house with one telephone line. The probabilities that when the telephone rings, the call is for A,B and C are 0.1, 0.5 and 0.6 respectiviely. The probabilities that A,B and C are in the house when the telephone rings are 0.7, 0.5 and 0.9 respectively. By assuming that all the probabilities above are independent of one another, find the probabilities that, when the telephone rings,
( a ) no one is in the house
( b) the call is for A who is not in the house
谢谢! |
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