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有关log的问题: 各位帮帮忙!
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本帖最后由 ting_006 于 8-6-2011 11:35 AM 编辑
有关log的问题:
各位帮帮忙!
1.logarithm of 28 with respect to base x=4
what is the value of x??
ans:2.3
2.(5 to the power of x+1)(2 to the power of x+2)=(3 to the power of x+3)
Find the value of x.
ans:0.25
3.Solve the following question.
a. Logarithm of (2x to the power of 2)-5 with respect to base 3=2+logarithm of (x-1) with respect to base 3
ans:4
b. logarithm of x to the power of 3 with respect to base 8=(logarithm of 8 to the power of 3 with respect to base x)+8
ans:1/2,512
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发表于 8-6-2011 12:08 PM
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1. logx 28 = 4
logx 28 = logx x^4
28=x^4
x = 2.3 |
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楼主 |
发表于 9-6-2011 10:13 AM
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发表于 9-6-2011 11:19 AM
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回复 3# ting_006
一群死高手不要来帮忙
.(5 to the power of x+1)(2 to the power of x+2)=(3 to the power of x+3)
Find the value of x.
5^(x+1) 2^(x+2) = 3^x+3
5(5^x) 4(2^x) = 27(3^x)
20(10^x) = 27(3^x)
(10/3)^x = 27/20
x log (10/3) = log 27/20
x= log (27/20) /l og (10/3)
then use calculator
ans:0.25
3.Solve the following question.
a. Logarithm of (2x to the power of 2)-5 with respect to base 3=2+logarithm of (x-1) with respect to base 3
log3 (2x^2 - 5) = 2+ log3 (x-1)
log3 (2x^2 - 5) - log3 (x-1) = 2
log3 (2x^2 - 5)/(x-1) = 2
(2x^2 - 5)/(x-1) = 3^2 = 9
2x^2 - 5= 9x-9
2x^2 -9x+4 =0
(2x-1)(x-4)=0
x= 1/2 , 4
ans:4
b. logarithm of x to the power of 3 with respect to base 8=(logarithm of 8 to the power of 3 with respect to base x)+8
log8 x^3 = logx 8^3 + 8
= 3 logx 8 +8
= 3/log8 x + 8
3 log8 x - 3 /log8 x =8
let log8 x = a
3a- 3/a = 8
3a^2 -3 =8a
3a^2 - 8a - 3 =0
(3a+1)(a-3)=0
a= - 1/3 , 3
log8 x = -1/3 , 3
x = 8^(-1/3) , 3
x= 1/8^(1/3) , 8^3
= 1/2 , 512
ans:1/2,512 |
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楼主 |
发表于 10-6-2011 09:27 PM
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本帖最后由 ting_006 于 10-6-2011 09:28 PM 编辑
回复 4# peaceboy
嘻嘻!!!
谢谢你的帮忙!!!!
真的很感谢哦~~
kangsahaimida!!! |
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楼主 |
发表于 11-6-2011 10:43 AM
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4.a)Find the least integral value of x such that (0.7)to the power of x+3 <0.01
Ans:10
b)Find the values of x that satisfy the inequality :
3 to the power of 2x -10(3 to the power of 3x)+9 is less than and equal to 9
ans:0 less than or equal to x less than or equal to 2 |
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发表于 23-6-2011 12:16 AM
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回复 6# ting_006
4.a)Find the least integral value of x such that (0.7)to the power of x+3 <0.01
Ans:10
b)Find the values of x that satisfy the inequality :
3 to the power of 2x -10(3 to the power of 3x)+9 is less than and equal to 9
ans:0 less than or equal to x less than or equal to 2
4
a. 0.7^(x+3) < 0.01
(0.7^x )(0.7^3) < 0.01
(0.7^x) < 0.01/(0.7^3)
(0.7^x)< 10/343
log (0.7^x) < log (10/343)
x log 0.7 < log (10/343)
x > log (10/343) / log 0.7
x > 9.9114
integral value of x = 10 ,11.12,.....
so the least integral value of x is 10.
b. 3^(2x)-10(3^3x) + 9 ≤ 9 .....this inequality..?? |
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发表于 23-6-2011 09:40 AM
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回复 ting_006
4.a)Find the least integral value of x such that (0.7)to the power of x+3 log (10/ ...
Log 发表于 23-6-2011 12:16 AM 
log 来解决log的问题 |
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