NH3(g) + HCl(g) ---> NH4Cl(s)
Calculate the heat change when 85g of ammonia react with 328.5g of hydrogen chloride gas.
n(NH3)=5 mol
n(HCl)=9 mol
通常都是1 mol of NH4 react with 1 mol of HCl to form 1 mol of NH4Cl,但是这里的HCl是excess的,请问我应该怎么做呢?我计算heat change的时候要把excess HCl计算在内吗?