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MT2的问题,帮帮忙!!!感谢!感谢!
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Prove sin(3a+b)+sin(a+3b)=2sin(a+b)(cos2a+cos2b)
要怎么样prove????麻烦各位帮帮忙。 |
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发表于 9-4-2012 06:38 PM
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Prove sin(3a+b)+sin(a+3b)=2sin(a+b)(cos2a+cos2b)
要怎么样prove????麻烦各位帮帮忙。
ting_006 发表于 9-4-2012 04:26 PM 
sin(3a+b)+sin(a+3b)=sin[2a+(a+b)]+sin[(a+b)+2b]
=sin(2a)cos(a+b)+cos(2a)sin(a+b)+sin(a+b)cos(2b)+cos(a+b)sin(2b)
=[cos(a+b)][sin(2a)+sin(2b)]+[sin(a+b)][cos(2a)+cos(2b)]
=[cos(a+b)][sin[(a+b)+(a-b)]+sin[(a+b)-(a-b)]+[sin(a+b)][cos(2a)+cos(2b)]
=[cos(a+b)][sin(a+b)cos(a-b)+cos(a+b)sin(a-b)+sin(a+b)cos(a-b)-sin(a-b)cos(a+b)]+[sin(a+b)][cos(2a)+cos(2b)]
=[cos(a+b)][2sin(a+b)cos(a-b)]+[sin(a+b)][cos(2a)+cos(2b)]
=[sin(a+b)][2cos(a+b)cos(a-b)]+[sin(a+b)][cos(2a)+cos(2b)]
=[sin(a+b)][cos(2a)+cos(2b)]+[sin(a+b)][cos(2a)+cos(2b)]
=2[sin(a+b)][cos(2a)+cos(2b)] |
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楼主 |
发表于 9-4-2012 08:27 PM
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回复 2# Allmaths
感谢感谢!!!!!!!!!^_^ |
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