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帮我回答问题
Given that 2a = 3b = 18c
Show that
ab=c(b+2a) |
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发表于 23-2-2011 06:20 PM
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帮我回答问题
Given that 2a = 3b = 18c
Show that
ab=c(b+2a)
vincentwyh 发表于 23-2-2011 06:08 PM 
是2^a=3^b=18^c 吗? |
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楼主 |
发表于 23-2-2011 06:21 PM
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发表于 23-2-2011 06:24 PM
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帮我回答问题
Given that 2a = 3b = 18c
Show that
ab=c(b+2a)
vincentwyh 发表于 23-2-2011 06:08 PM 
Let x=2^a=3^b=18^c
then x^(1/a)=2
x^(1/b)=3
x^(1/c)=18
since 2*(3^2)=18,
then [x^(1/a)][x^(2/b)]=x^(1/c)
(1/a)+(2/b)=1/c
ab=c(b+2a) (shown) |
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楼主 |
发表于 23-2-2011 06:38 PM
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回复 4# Allmaths
谢谢!! |
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发表于 23-2-2011 06:40 PM
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回复 Allmaths
谢谢!!
vincentwyh 发表于 23-2-2011 06:38 PM 
不客气.. |
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楼主 |
发表于 23-2-2011 06:40 PM
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下一题
If 3(4^p) = 5(2^q) and 9(8^p)= 10(4^q) , show that 2^(p+1)=5 |
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发表于 23-2-2011 06:49 PM
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下一题
If 3(4^p) = 5(2^q) and 9(8^p)= 10(4^q) , show that 2^(p+1)=5
vincentwyh 发表于 23-2-2011 06:40 PM 
3(4^p)=5(2^q)
(3/5)(4^p)=2^q ---eq 1
9(8^p)=10(4^q)
9(8^p)=10(2^q)^2 ---eq 2
Sun eq 1 into eq 2,
9(8^p)=10[(3/5)(4^p)]^2
9(8^p)=10[(3/5)(4^p)]^2
simplify 就可以了。。。 |
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楼主 |
发表于 23-2-2011 07:06 PM
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在一次谢谢!! |
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楼主 |
发表于 23-2-2011 11:01 PM
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如何做这题?
Show that 2^n +2^(n+1) + 2^(n+2) is divisible by 7 where n is a positive integer. |
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发表于 7-3-2011 02:36 PM
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如何做这题?
Show that 2^n +2^(n+1) + 2^(n+2) is divisible by 7 where n is a positive integer.
vincentwyh 发表于 23-2-2011 11:01 PM 
2^n +2^(n+1) + 2^(n+2)=2^n+(2)2^n+(2^2)(2^n)
=2^n+(2)(2^n)+(4)(2^n)
=7(2^n)
hence, it's divided by 7 |
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