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查看: 1016|回复: 3
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化学高手进来下~
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楼主 |
发表于 12-12-2010 05:04 PM
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可怜0回复 |
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发表于 12-12-2010 05:23 PM
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HCOOH is weak acid,HCOOK is salt of HCOO-
the solution is buffer..
if want to find pH,jz substitute formula
pH= -log Ka-log(conc of acid/conc of salt)
= -log 1.74^-4 - log ( 0.3/0.52)
=4.008
= 4.1 |
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楼主 |
发表于 12-12-2010 08:05 PM
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回复 3# sookchin
娃哈哈!谢谢你~知道我哪里错了~粗心啊!con. base 和con.acid倒转了 |
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